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The great German poet and aesthetician, Friedrich von Schiller , propounded the question of aesthetic education on the basis of the state of existence and split personality of his day.

德国伟大的诗人、美学家席勒根据他所处时代人的生存状态、人性的分裂，提出了美育问题。

I like my pathology teacher---professor liu ,he is very affability and kindness and with frofound knowlodge.he can always makes us understand the complex question clearly.

"我喜欢我的病理学老师刘教授，他和蔼可亲，学识渊博，他总是可以将复杂的问题讲得很透彻。"

One of the major issues affecting nineteenth-century China was the question of how to deal with other countries.

的主要问题之一影响19世纪中国的问题是如何处理与其他国家。

So the question now is what type of affiliate marketing will work best for you?

所以，现在的问题是什么类型的联盟营销工作最适合你？

Question 6 Are you prepared to work in any affiliated company of shell Limited or any other country world-wide?

你是否愿意去壳牌的任一公司或任何国家工作？

First, we introduce and discuss the various methods of multivariate polynomial interpolation in the literature. Based on this study, we state multivariate Lagrange interpolation over again from algebraic geometry viewpoint:Given different interpolation nodes A1,A2 .....,An in the affine n-dimensional space Kn, and accordingly function values fi(i = 1,..., m), the question is how to find a polynomial p K[x1, x2,...,xn] satisfying the interpolation conditions:where X=(x1,X2,....,xn). Similarly with univariate problem, we have provedTheorem If the monomial ordering is given, a minimal ordering polynomial satisfying conditions (1) is uniquely exsisted.Such a polynomial can be computed by the Lagrange-Hermite interpolation algorithm introduced in chapter 2. Another statement for Lagrange interpolation problem is:Given monomials 1 ,2 ,.....,m from low degree to high one with respect to the ordering, some arbitrary values fi(i= 1,..., m), find a polynomial p, such thatIf there uniquely exists such an interpolation polynomial p{X, the interpolation problem is called properly posed.

文中首先对现有的多元多项式插值方法作了一个介绍和评述，在此基础上我们从代数几何观点重新讨论了多元Lagrange插值问题：给定n维仿射空间K~n中两两互异的点A_1，A_2，…，A_m，在结点A_i处给定函数值f_i(i=1，…，m)，构造多项式p∈K[X_1，X_2，…，X_n]，满足Lagrange插值条件：p=f_i，i=1，…，m (1)其中X=(X_1，X_2，…，X_n)，与一元情形相似地，本文证明了定理满足插值条件(1)的多项式存在，并且按"序"最低的多项式是唯一的，上述多项式可利用第二章介绍的Lagrange-Hermite插值算法求出，Lagrange插值另一种描述是：按序从低到高给定单项式ω_1，ω_2，…，ω_m，对任意给定的f_1，f_2，…，f_m，构造多项式p，满足插值条件：p=sum from i=1 to m=Ai=f_i，i=1，…，m (2)如果插值多项式p存在且唯一，则称插值问题适定。

There's a big difference between an affirmation and a question.

肯定和疑问的语气是有很大的不同的。

His answer to this question is affirmative.

他对这个问题的回答是肯定的。

For example:his answer to this question is affirmative.

他对这个问题的答案是肯定的。

Do you need to be fluent in the language to answer that question affirmatively?

你必须能操流利的语言回答这个问题肯定？

If you were not , and OS X just booted normally, have no fear.

如果你没有，和OS X刚刚启动通常，没有恐惧。

I only want to preserve our all .

我只想保存好我们的一切