查询词典 integer linear optimization

The results indicated that the piecewise linear function approach was easy to model nonlinear unit consumptions with a higher accuracy without regressing any parameter, and the related model could be solved quickly for a medium size problem.Meanwhile, the piecewise linear function approach could simultaneously handle nonlinearities of multi raw materials in a unit without adding any new integer variable.

案例结果表明，分段线性函数不需要回归参数，建模简单，精度较高，对于中等规模问题求解时间短，能够同时处理装置的多种原料非线性单耗，而不需要增加新的整数变量，多项式函数则不具有这些优点。

In this paper, we shall apply this concept to the ring of linear operators on Banach space X and prove that if a linear operator T on a Banach space X is defined in all of X and has finite descent and ascent then there is a Drazin inverse T~D satisfying TT~DT~k=T~k, T~DTT~D= T~D, and T~DT=TT~D for some nonegative integer k.

以后又对方阵的Drazin逆作了深入的研究。它的一些性质可以参阅。同时对它的应用也作了许多研究，例如可以把Drazin逆的概念应用到Markov过程、线性微分方程组、差分方程组和最优控制等方面。

Jon Edvardsson et al pointed out that the technique developedby Neelam Gupta et al is neither complete nor terminational for W on which all of thepredicate functions with respect to the input variables are linear, and suggested usinglinear programming and linear integer programming methods instead.

Jon Edvardsson等人指出，对于谓词函数均为输入变量的线性函数的程序路径， Neelam Gupta等人提出的求解方法是不完备的和非终止的，并建议采用线性规划、线性整数规划方法。

This article outlines the integer aliquot concept in the first primary theory of numbers, the basic nature, as well as some special integer divisible characteristics.

本文先概述初等数论中整数的整除概念、基本性质，以及一些特殊整数的可除性特征。

Carries on the classification to the question, analyzes each kinds of questions the explanation mentality, inquires and summarizes that it can 100 within the odd number aliquot aliquot characteristic, finally discovered that any integer can by the lowliest place digit be 1,3,7,9 aliquot integer characteristics according to the lowliest place numeric classification, each kind has certain rule.

对问题进行分类，分析各类问题的解答思路，探寻、总结出能被100以内奇数整除的整除特征，结果发现任何一个整数能被末位数字是1，3，7，9整除的整数特征可按末位数字分类，每一类都有一定的规律。

Finally, we obtain the solutions of the 0-1 Integer Programming problem. The most merit of the model is its automatization characteristic, and the model fits to solve arbitrary 0-1 Integer Programming problem having arbitrary variable element.

该模型的最大优点在于具有自动化的特点；同时，从理论上来讲，该模型适合含有任意变量的任意0-1整数规划问题的求解。

We studied the asymptotic properties of the integer part of the k-th root positive integer and gave an interesting asymptotic formula.

研究了一个关于正整数κ次根的整数部分序列的均值，并利用初等的方法得到了一个有趣的渐近公式： 3。

A verifier can be convinced that the committed number x is neither less than the integer a nor more than the integer baiter the protocol is operated only once, and hence the exact proof that x lies in the interval is achieved.

为了去掉这种方法上的重复性，通过联合运用两承诺值相等协议及CFT证明协议提出了一个证明承诺值位于特定区间的新协议，协议运行一次便可使验证者确信承诺值x位于区间中。

In the problem, there are m persons who are to be assigned to do n jobs, and the number of the persons who are assigned to do the jth job is bj, where bj is an unknown positive integer number to be calculated such that djbjej, dj and ej are known positive integer number (j=1,2,…,n) such that ∑nj=1bj=m and m≥n.

考虑一类较一般的最优指派问题：欲指派m个人做n项工作，要求每个人只做一项工作，第j项工作可以由bj个人共同去做，其中bj是待求未知数，满足dj≤bj≤ej(即ej，dj为第j项工作所需人数的上下限)及∑nj=1bj=m，dj，ej为已知常数，j=1，…，n。

In the thesis , we give combinatorial proof of some q-identities using integer partition.In the thesis some vital identities with binomial coefficient are given with their combinatorial proof, and the q-analogues of some identities are offered with corresponding combinatorial proof using integer partition.

本文给出了一些重要的二项式系数恒等式的组合证明或组合解释，并从分拆的角度给出了一些q-恒等式的组合证明，其中突出的成果是给出了平方和恒等式的一个直接的组合证明并给出了偶数平方和与奇数平方和的q-模拟及组合证明。

Fostering the concept of multi-culture firmly and mastering the development of advanced culture correctly are conductive to resisting terrorism, separatism of nationalities and ultraism of religion, which is of great academic theoretical, immediate and profound historical si...

牢固树立多元文化的理念和正确把握先进文化的发展方向，有助于在世界范围内自觉地抵制恐怖主义，民族分裂主义和宗教极端主义。不仅具有重大的学术理论意义，而且也具有重大的现实意义和深远的历史意义。

But if anyone walks in the night, he stumbles, because the light is not in him.

11：10 若在黑夜行走，就必碰跌，因为那光不在他里面。