查询词典 int.

The above all really justboils down to one special "int __bitwise" type.

上面那些实际都可以浓缩成一个特殊的"int __bitwise"类型。

Hey blah....... it could be an INT/SHORT.

嘿布拉赫。。。。。。。它可能是一个INT /短。

A string literal cannot be implicitly converted to an int, so the call is an error.

字符串字面值无法隐式地转换为 int 型，因而该调用是错误的。

The reason that these functions return an int is to allow them to return an end-of-file marker.

这些函数返回 int 值的原因是为了允许它们返回一个文件结束标记。

Regardless of that value, an enum or enumerator is always promoted at least to int.

无论其最大值是什么， enum 对象或枚举成员至少提升为 int 型。

In pre-Standard C++, a function without an explicit return type was assumed to return an int.

在 C++标准化之前，如果缺少显式返回类型，函数的返回值将被假定为 int 型。

The last expression causes a compile-time error because neither int nor string is implicitly convertible to the other.

最后一个表达式导致编译器错误，这是因为 int 和 string 都不能隐式转换成对方。

X is a real-type expression. The result is the fractional part of X; that is, Frac = X - Int.

Frac函数返回参数X的小数部分，X是一个实型数，该函数的作用等价于Frac=X-Int。

Theoretically it is impossible because index variable has int type.

理论上这是不可能的，因为指数变量int类型。

In the following case it is of type int.

在下面的情况下，它是int类型。

Methods: Five patients with parkinsonism or dystonia were assigned to general anesthesia using an modified endotracheal tube.

本实验依照人体实验之相关规定进行，五位患有帕金森氏症或肌张力异常的病人接受神经立体定位手术。

If you can benefit from this book, it is our honour.

如果您能从本书获益，这将是我们的荣幸。