查询词典 bordered matrix

On the basis of the research on shape of fish-head boudin and the difference between layer and matrix, and by means of the method of physical modeling, the author modeled different shapes of fish-head boudin, and came out the relationship between shape of fish-head boudin and viscosity ratio between layer and matrix, which can be called an experience rheological gauge.

在深入研究鱼嘴构造形态与能干层基质流变性差异的基础上，运用物理模拟的方法，模拟出不同形态的鱼嘴香肠构造，反演出能干层基质粘度比与香肠形态之间的关系，进而得出一种关於鱼嘴香肠构造的经验流变计。

On the basis of the research on shape of fishhead boudin and the difference between layer and matrix, and by means of the method of physical modeling, the author modeled different shapes of fishhead boudin, and came out the relationship between shape of fishhead boudin and viscosity ratio between layer and matrix, which can be called an experience rheological gauge.

在深入研究鱼嘴构造形态与能干层基质流变性差异的基础上，运用物理模拟的方法，模拟出不同形态的鱼嘴香肠构造，反演出能干层基质粘度比与香肠形态之间的关系，进而得出一种关于鱼嘴香肠构造的经验流变计。

Firstly, the decision matrix is transformed into an objective matrix, and then the weight of every objective is determined by means of entropy coefficient method. By Integration of experts' knowledge, the acceptable lower bound of degree of satisfaction and acceptable upper one of degree of dissatisfaction of every objective are decided. At last, by using the weight vector and the acceptable lower boun...

首先将决策矩阵转化为目标矩阵，然后利用熵权系数法计算各个目标的权重，综合专家的意见得到对于每个目标可以接受的满意度的下界和不满意度的上界，最后利用得到的权重向量以及得到的满意度的下界和不满意度的上界计算各方案的vague估计值，将得到的vague估计值按照评分函数进行排序，得到方案的排序结果。

From [1], Every transition function is a positive strongly continuous semigroup of contractions on l\, but it isnt a strongly continuous semigroup on l_∞- In fact, the sufficient and necessary condition for a transition function to be a strongly continuous semigroup on l_∞ is that the q—matrix Q is an uniformly bounded q—matrix on l_∞- This is the trivial case.

由Anderson[1]知道转移函数P是l_1空间上正的强连续压缩半群，但P一般来说不是l_∞空间上的强连续半群，而P是l_∞上强连续半群的充要条件是q—矩阵Q是l_∞。

Based on the point that there is something in common between the rules of matrix multiplication and the figure connection in braid multiplication, this paper gave a new representation of braid group called node matrix representation.

利用矩阵乘法规则与辫子乘法中图形的上下对应连接有类似之处这一特点，提出一种用结点矩阵表示辫子的方法。

Rules for fusing, which specify the possible values of the charge that can be obtained when two particles of known charge are combinedbtogether, used for reading out information. In the #nu=5/2# FQH state, it can be realized by measuring whether each pair annihilates fully or not with interference experiment. The representation of the braid group realized by n anyons is cmpletely characterized by the R-matrix and F-matrix which satisfy a pentagon equation and a hexagon equation, coherence conditions for the corresponding anyon model.

满足一定的聚合规则，用于信息读取（在填充因子为5/2的分数量子霍尔效应中，可以通过干涉实验测量每对相邻的粒子相聚合的湮灭情况来实现信息读取）；N个任意子组成的体系的标准基中辫子群表示可以完全由R矩阵和F矩阵决定，不同任意子模型中的R矩阵和F矩阵的具体形式可以通过五边形和六边形方程求出。

The aim of the paper is to receive nodal impedance matrix by adding- branch line algorithm and admittance matrix algorithm, to analyze the effect of them, and to provide the models.

使用了支路追加法和导纳矩阵求逆法来形成节点阻抗矩阵，给出了两种算法的数学模型，分析了算法各自的特点和优势。

The pupose of the research is to develops public key encryption and digital signature shemes based on matrix canonical decomposition problem, or matrix diagonalization problem over Z/n, the ring of integers with modulo-n addition and multiplication in particular, where n is an RSA modulus.

本课题研究基于矩阵经典分解问题，特别是Z/n上矩阵对角化问题的公钥密码与数字签名算法，其中n是一个RSA模数。新算法采用由一个矩阵多项式构成的多维单向陷门函数，其单向性由矩阵对角分解问题(即通过相似变换将矩阵化为对角型的问题)的复杂性来保障，对该函数求逆的陷门由矩阵的特征值或特征向量提供。

In this paper,similar canonical form of involutory matrix on integral number ring is given,and we prove that similar canonical form of involutory matrix is unique.

给出了整数环上对合矩阵的相似标准型，并证明了其唯一性。

The solvent travels up the matrix by capillarity, moving the components of the samples at various rates because of their different degrees of attachment to the matrix and solubility in the developing solvent.

溶剂通过毛细现象而沿板上升。由于样品中各组分对基质的吸附程度不同，它们在显色溶剂中的溶解度也不同，所以它们在溶剂中以不同的速率移动。

We were cousins—his grandfather was King of Scots,and his great-grandfather was Henry VII of England.

我们是堂姐弟——他的祖父曾是苏格兰国王，他的曾祖父是英格兰的亨利二世。

I do want to help you, but I am in a quandary now!

我是想帮你，但是我现在左右为难啊！