查询词典 adjoint differential expression

Further, according to the positity of the Hessian matrix, which is got from the second order adjoint model, the uniqueness of the assimilation result is manifest. And the relationship between the rate of convergence and the frequency of the observation utilization in the assimilation is investigated.

进一步，借助二阶伴随模式所得到的Hessian矩阵，说明同化解是唯一的，并分析了优化算法的收敛速度与同化过程中观测资料使用频率的关系。

Special considerations are given to spatial discretization of hyperbolic equation with non self-adjoint operator nature.

同时构造了一个用于求解此耦合过程的统一混合弱形式，并且针对其中具有非自伴随算子特性的双曲线控制方程的空间离散进行了特殊考虑。

In this paper, by computing the Laplace of the square of the length of the second fundamental form and introducing a self-adjoint operator and using Stokes Theorem and Hopf Theorem, we obtained some pinching theorems and rigidity theorems for hypersurfaces and submanifolds in hyperbolic space.

本论文通过计算双曲空间中子流形的第二基本形式模长平方的拉普拉斯和引进一个新的自共轭二阶算子，利用Stokes定理和Hopf定理得到了子流形的一些拼挤定理和刚性定理。

Mainly in a method of the lattice vector quantifying coding and decoding, a new basic code book is selected out and directly or indirectly comprises all points whose value is less than or equal to 3 of any dimension in a RE point set, and points on a fourth grade hypersphere in the basic code book are all odd points so that part of nearest adjoint point values can be comprised in the basic code book only via corresponding odd number processing.

一种格矢量量化编解码的实现方法及装置，其主要是在格矢量量化编码方案中，选定新的基础码本，在该基础码本中直接或间接地包含了RE 8 点集中任意维的数值小于等于3的所有点，且该基础码本中的第4级超球面上的点全部为奇数点，以使得部分的最近邻点数值仅经过相应的奇数化处理便可以包含于基础码本中。

The research of this thesis focuses on the infimum and supremun of self-adjoint operators in a complex Hilbert space with respect to the Gudder order, the infimum and supremun of operators in a complex Hilbert space with respect to the *-order and theΓ-inverse of operators in a complex Hilbert space.

本文研究内容涉及Hilbert空间上自伴算子关于Gudder序的上确界和下确界，Hilbert空间上算子关于~*-序的上确界和下确界以及Hilbert空间上算子的Γ-广义逆这三个方面的内容。

For self-adjoint operators A and B, we show that there exists A∧_G B and establish the explicit representation of A∧_G B, where A∧_G B denotes the infimum of A and B associated with the Gudder order.

本文共分为三章，各章的主要内容如下：第一章通过空间分解和算子分块，研究了Hilbert空间上自伴算子关于Gudder序的确界性质。

According to [2], we know that if X is a reflexive Banach space and T is a strongly continuous semigroup on X with the infinitesimal generator A, then the adjoint semigroup T~* is also a strongly continuous semigroup on X* and its infinitesimal generator is A~*, the ajoint operator of A.

由文献[2]我们知道，如果X是一自反Banach空间，那么X上强连续半群T的对偶半群T~*也是X~*上的强连续半群，并且其无穷小生成元为半群T的无穷小生成元的对偶。

For a given Sturm-Liouville equation with positive leading coefficient function, by use of the monotonicity results of its natural loops, limit of boundary conditions and eigenvalues in the space of self-adjoint boundary conditions, a proof of the equalities among eigenvalues for coupled boundary conditions and those for separated boundary conditions is made.

内蒙古工业大学理学院副教授 2。对于给定的首相系数函数为正的 Sturm-Liouville方程，利用在自伴边界条件空间上自然圈、边界条件的极限和特征值的单调性的几个结果，给出了在偶合边界条件与分离边界条件下的特征值间的一些等式的证明。

The proof shows that any functor which is a left adjoint is right exact.

该证明指出，任一函子，如果是一个左伴随，就右正合。

When the nonlinearity is an odd function, multiple positive solutions for the sec-ond order self-adjoint difference equation with the Neumann boundary conditionΔu(0)= 0,Δu = 0 are obtained by applying Clark's theorem.

另一方面，当非线性项非负且在0~+和+∞是渐近线性的情况下，应用山路引理研究了方程在混合边值条件u(0)= 0，Δu = 0下正解的存在性。

We stopped by the old fashion ice cream parlor Manhattan Beach Creamery for some refreshment. The "No Shoes, No Shirt, No Problem" sign on the wall epitomizes the beach lifestyle.

我们去商店区的一家老式冰淇淋店坐坐，墙上挂著「没鞋，没上衣，没问题」的牌子完全捕捉了海滩生活的随性及风格。

"If therefore", argues Bellarmine we can offer our prayers and our satisfactions in behalf of those detained in purgatory, because we are members of the great body of Christ, why may not the Vicar of Christ apply to the same souls the superabundant satisfaction of Christ and his saints--of which he is the dispenser?

" "因此，如果"，认为贝拉明（德indulgentiis ，十四）"我们可以提供我们的祈祷和我们满意的代表那些被拘留在炼狱，因为我们是成员的伟大基督的奥体，为什麼可能不是牧师基督适用於同样的灵魂满意的过剩是耶稣和他的圣人-他是在配药？