查询词典 integer
- 与 integer 相关的网络例句 [注:此内容来源于网络,仅供参考]
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Genius - Genius is an arbitrary precision integer and multiple precision floating point calculator.
Genius是一个任意精度的整型和多精度浮点型计算器。
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Based on the difference, the ISIs collected from the injured dorsal root ganglion neurons discharge are analyzed. The results suggest that there are some nonlinear deterministic factors in the integer multiple fire of injured dorsal root ganglion neurons.
从这种差别出发,分析了实验中整数倍放电的ISI 序列,得到该ISI 序列是可非线性预报的,这表明大鼠损伤背根节神经元自发放电中的整数倍放电更可能是由确定性机制所产生的
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Op1 + op2 The addition operator will add two numbers. op1 - op2 The subtraction operator will subtract two numbers. op1 * op2 The multiplication operator will multiply two numbers. op1 / op2 The division operator will divide two numbers. op1 % op2 The modulus operator will return the remainder of the division of two integer operands. op1 xx op2 The exponentiation operator will raise op1 to the power of op2.++op1 The pre-increpment operator will increase the value of op1 first, then assign it. op1++ The post-increment operator will increase the value of op1 after it is assigned.--op1 The pre-decrement operator will decrease the value of op1 before it is assigned. op1-- The post-decrement operator will decrease the value of op1 after it is assigned.
op1 + op2 对两个数值做加法操作 op1 - op2 对两个数值做减法操作 op1 * op2 对两个数值做乘法操作 op1 / op2 对两个数值做除法操作 op1 % op2 求两个整型数值的余数 op1 xx op2 求幂操作:求 op1 的 op2 次幂++op1 前加操作: op1 的值先增加,然后将值赋给自身 op1++后加操作: op1 的值先赋给自身,再增加值--op1 前减操作: op1 的值先减少,然后将值赋给自身 op1—后减操作: op1 的值先赋给自身,再减少值
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In 1997, Lenhard Ng Michelle Schultz[1] gave the definition of k -ordered Hamilton graphs,namely, let G be a Hamiltonian graph of order n,and for a positive integer k with k ≤n, we say that G is k -ordered if for every sequence S : v1 , v2,Λ,vk of k distinct vertices, there exists a hamiltonian cycle C of G such that the vertices of S are encountered on C in the specified order.
年, Lenhard Ng Michelle Schultz[1]给出k-可序( k ?ordered)哈密尔顿图的定义,即设G是n阶哈密尔顿图,对于正整数k,称G 是k -可序图,如果对于任意给定的k 个互不相同的顶点的有序子集S =( v1 ,v2,Λvk)( 2≤k ≤n),存在G中的哈密尔顿圈C 包含S 且不改变其中元素的顺序。2000 年,R.J。
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On some machines a char whose leftmost bit is 1 will be converted to a negative integer ("sign extension").
在某些机器中,如果char类型值的最左一位为1,则转换为负整数。
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By constructing a job-schedule network that can present job-time relationship,the FJSP is transformed to a network flow problem,and a 0-1 integer programming mathematical model is developed.
针对一般形式的固定工件排序问题(即可用机器数是有限的,存在机器与工件间匹配约束,以机器分配成本最小为优化目标),作者通过建立描述工件间时序关系的工件时序网络,将固定工件的排序问题转化为沿工件时序网络的网络流问题,并建立了0-1整数规划数学模型。
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If no control with the integer ID given by the nID parameter exists, the value is NULL.
如果没有控件具有nID给出的整数ID,则返回NULL。
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In Python, like in C, any non-zero integer value is true; zero is false.
在 Python 中,类似于 C 任何非零值为真,零为假。
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Nonnegative integer less than the number of items in the sequence, and thesubscription selects the item whose index is that value.
计算结果必须是小于基元中元素数的非负整数,并且此下标操作选择以该数为索引(从0开始计)的值。
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The resulting value must be a nonnegative integer less than the number of items in the sequence, and the subscription selects the item whose index is that value.
计算结果必须是一个小于主元中所含项数的非负整数,并且此下标操作选择以该数为索引(从0开始计)的值。
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- 推荐网络例句
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Pachomius manual labour was organized as an essential part of the monastic life; and since it is a principle of the monks as distinguished from the mendicants, that the body shall be self-supporting, external work of one sort or another has been an inevitable part of the life ever since.
根据圣pachomius体力劳动组织作为一个重要组成部分寺院生活;以来,这是一个原则的和尚,作为有别于乞丐,该机构应自支撑,对外工作的这种或那种已一个必然的一部分,生活至今。
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In order to study the effects of parametrical rolling on the ship movement and tilts, in allusion to ship's navigating in regular following waves, the equation of ship rolling motion is transformed into normal Mathieu equation by proper variable replacement when strong parametrical excitation in restoring moment varied according to sine or cosine wave.
为研究参数横摇对船舶运动和倾覆的影响,通过对船在规则波上随浪航行时,恢复力矩中出现的1个以正余弦规律变化的强参数激励项进行适当的变量置换,将船舶的横摇运动方程转换成标准形式的Mathieu方程。
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I agree with you that three-fourths of al your road equipment should be replaced.
我同意你有关3/4的公路设备都要更换的建议。