backward difference operator

backward difference operator的基本解释

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[计] 后向差分算子

与backward difference operator相关的网络例句 [注：此内容来源于网络，仅供参考]

The results were as follows.(1) In the backward handspring, the trajectory of CM and horizontal velocity of CM in junior-high and college gymnasts were lower and higher than those of senior-high gymnast, so the vertical velocity is better when they perform tucked backward somersault. College gymnast has higher vertical velocity than junior-high and senior-high gymnasts in take-off moment of backward handspring phase.(2) Senior-high and college gymnasts have more elbow and shoulder angle in take-off moment of backward handspring and tucked backward somersault phase. Therefore, angle of both arm is bigger for performing in hand push away phase in the backward handspring, and increased the reaction force with body in the tucked backward handspring.(3) College gymnast has large knee flexions in hand support and push away moment in the backward handspring, it would increase rotation radius and better moments of inertia in the backward handspring.

结果显示：在后手翻阶段中，较低的重心轨迹和较高的水平速，有於后续空翻的垂直速；大专选手在后手翻阶段起跳瞬间有较高的垂直速；高中及大专选手在后手翻起跳脚地瞬间和团身后空翻起跳脚地瞬间时，肘、肩关节角皆大於国中选手，使其在后手翻起跳地瞬间时，双臂的伸展於后手翻的手推地面的动作，而团身后空翻起跳脚地时，双臂向上摆於身体向上伸展方向的掌握，并使重心有一定的腾空高；大专选手在后手翻阶段的手著地瞬间和手地瞬间的膝关节角较大於高中和国中选手，使其可增加身体的旋转半径，并能获得较佳的下摆动能，而膝关节角小则形成屈膝的动作，导致重心水平速低，减少下摆动能和影响整体动作的节奏和韵。

Op1 + op2 The addition operator will add two numbers. op1 - op2 The subtraction operator will subtract two numbers. op1 * op2 The multiplication operator will multiply two numbers. op1 / op2 The division operator will divide two numbers. op1 % op2 The modulus operator will return the remainder of the division of two integer operands. op1 xx op2 The exponentiation operator will raise op1 to the power of op2.++op1 The pre-increpment operator will increase the value of op1 first, then assign it. op1++ The post-increment operator will increase the value of op1 after it is assigned.--op1 The pre-decrement operator will decrease the value of op1 before it is assigned. op1-- The post-decrement operator will decrease the value of op1 after it is assigned.

op1 + op2 对两个数值做加法操作 op1 - op2 对两个数值做减法操作 op1 * op2 对两个数值做乘法操作 op1 / op2 对两个数值做除法操作 op1 % op2 求两个整型数值的余数 op1 xx op2 求幂操作：求 op1 的 op2 次幂++op1 前加操作： op1 的值先增加，然后将值赋给自身 op1++后加操作： op1 的值先赋给自身，再增加值--op1 前减操作： op1 的值先减少，然后将值赋给自身 op1—后减操作： op1 的值先赋给自身，再减少值

The introduction of displacement operator, derivation operator, integral operator and the operator, such as differential calculus operator and the definition of the form of computing, will be applied to similar derivation formula gives Newton a Kete Si formula and Bernstein theorem Law said the operator, and form is derived; linear differential equations is the operator solution.

有没有高手可以帮我翻译下这段话啊？？？引入位移算子、求导算子、积分算子和差分算子等微积分算子的定义及其形式运算，将其应用于近似求导公式；给出牛顿一柯特斯公式和伯恩斯坦定理的算子法表示，并进行形式推导；给出线性常微分方程的算子解法。

与backward difference operator相关的网络解释 [注：此内容来源于网络，仅供参考]

backward difference operator：后向差分算子

backward difference method 后向差分法 | backward difference operator 后向差分算子 | backward difference 后向差分

backward difference operator：反向差分运算子

反向差分法 backward difference method | 反向差分运算子 backward difference operator | 反向微分法 backward differentiation method

backward difference operator：向后差分算子

向后差分 backward difference | 向后差分算子 backward difference operator | 向后消去程序 backward elimination procedure