查询词典 exponentiation

Op1 + op2 The addition operator will add two numbers. op1 - op2 The subtraction operator will subtract two numbers. op1 * op2 The multiplication operator will multiply two numbers. op1 / op2 The division operator will divide two numbers. op1 % op2 The modulus operator will return the remainder of the division of two integer operands. op1 xx op2 The exponentiation operator will raise op1 to the power of op2.++op1 The pre-increpment operator will increase the value of op1 first, then assign it. op1++ The post-increment operator will increase the value of op1 after it is assigned.--op1 The pre-decrement operator will decrease the value of op1 before it is assigned. op1-- The post-decrement operator will decrease the value of op1 after it is assigned.

op1 + op2 对两个数值做加法操作 op1 - op2 对两个数值做减法操作 op1 * op2 对两个数值做乘法操作 op1 / op2 对两个数值做除法操作 op1 % op2 求两个整型数值的余数 op1 xx op2 求幂操作：求 op1 的 op2 次幂++op1 前加操作： op1 的值先增加，然后将值赋给自身 op1++后加操作： op1 的值先赋给自身，再增加值--op1 前减操作： op1 的值先减少，然后将值赋给自身 op1—后减操作： op1 的值先赋给自身，再减少值

The implementation processes of those two algorithms on smart card with cryptographic coprocessor are explained separately. The implementation process of RSA includes modular exponentiation and modular multiplication. The process of ECC includes the selection of base field and coordinates, scalar multiplication and field operation.

本文分别阐述了两者在带有加密协处理器的智能卡平台上的实现过程，包括RSA算法中模幂运算、模乘运算的实现；ECC算法中基域的选择、坐标系的选择、标量乘法和域算术运算的实现。

In LabVIEW 6.0 and greater, the ^ symbol means something else entirely (bit-wise XOR), and the ** symbol is exponentiation.

在LabVIEW6.0或之后的版本中， ^符号表示的是完全别的东西(比特运算的XOR，异或)，而用**符号表示幂运算。

His female bullfighter Lydia gradually Health love, but she was in a vegetative state after the Bulls Zhuangcheng away from her, just because Lydia's ex-boyfriend showed more affectionate than he is like love.

他对女斗牛士莉迪亚渐生爱意，却在她被公牛撞成植物人后离她而去，仅仅因为莉迪亚的前男友表现出好似比他更深情的爱。

I know of none which are not easy to answer, but what I am trying to do now is only by a series of hints to throw some light on the narrow path of legal doctrine, and upon two pitfalls which, as it seems to me, lie perilously near to it.

我不认为有什么难以回答的问题，但我现在要做的仅仅是通过一系列线索，来给法律理论的狭窄路径以及在我看来离它近得危险的两个陷阱提供一些启示。