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ax相关的网络例句
与 ax 相关的网络例句 [注:此内容来源于网络,仅供参考]

Very well,there is the ax.

好,斧头就在那儿。

For example, the handle of the ax broke one day.

比如,有一天斧头的把手断了。

And at last he was caught by the owner of the ax.

最后他被斧头的主人给抓住了。

Very well , there's the ax.

""好,斧头就在那儿。

The first traveler tried to hide the ax, but he did not know where to hide it.

第一个人尝试把斧头藏起来,但是他不知道该藏在何处。

This is my ax.

这是我的斧子。

Nice to meet you! I've lost my ax into the pond by mistake.

我不小心把我的斧子丢到池塘里了。

In this paper, an extended divide and conquer algorithm is intended proposed, which is for solving the real symmetric band generalized eigenvalue problem under distributing environment Eigenvalue partition theorem is presented and proved Based on divide and conquer by extension, this algorithm computes generalized eigenpaires of symmetric band matrix pencil by bisection and generalized Rayleigh quotient iteration Theoretic analysis and numerical results show that this algorithm is better than the classic software package LAPACK when bandwidth is small and the scale is large Combined with multisection, which has good parallelism, it got good effects under distributed environments

提出了分布式环境下计算对称带状广义特征值问题的一种扩展分治算法,给出了特征值分割定理及其证明算法在扩展分治的基础上,利用二分压缩结合广义Rayleigh商迭代计算广义特征对理论分析和数值实验表明,对于窄带宽大规模的广义特征值问题,该分治算法明显优于LAPACK软件包结合并行性好的多分法,在分布式环境下获得了很好的并行效果1 引言本文研究了对称带状广义特征值问题Ax =λBx ( 1)的并行计算,其中,A ,B均为半带宽为r的n阶实对称带状矩阵且其中之一是正定的本文总假设B是正定的求解此问题有两种传统方法,第1种方法是通过计算矩阵B的Cholesky分解,将问题( 1)转化为标准特征值问题[1~3] ,进一步

The position,pathway and drainage of the brachial,basilic and ax- illary veins in 81 upper extremities of 50 cadavers had been observed.

在50例尸体上对81侧上肢的肱静脉、贵要静脉和腋静脉的位置、流注进行了观察。

He looks as though he would ' rush out with a battle-ax on his shoulder to meet a chariot.

他看来,他将'冲出了战斗斧对他的肩膀,以满足战车。

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相关中文对照歌词
Pass The Ax
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Next time I see you,I shall give you a black eye.

下次我看见你,我会打你一顿。

In this paper,design scheme of classification system of wood surface color is established.

提出了木质板材颜色分类的系统设计方案。

With a few exceptions (a sea-monster attack seems to go on forever), this is where the film outdoes its predecessor.

不出什么意外(似乎永远都有海怪的攻击),这可能是这部片优于前作的地方了。